Arithmetic Progression (A.P) and Geometric Progression (G.P)
Arithmetic Progression (A.P)
An AP is a sequence in which the terms
increase or decrease by a constant number, called Common Difference.
Let a, a+d, a+2d, a+3d …………… are
said to be in A.P, in which
1st term = a, Common Difference = d & n= no. of terms
1. nth term or
last term = tn = a + (n-1)d
2. Sum of ‘n’
terms = Sn = n/2 [2a + (n-1)d] = n/2 [a + tn]
Examples
1. 1. Find the sum
of the first 20 terms of the AP; 5,2,-1,-4,-7………..
Solution:
Here a= 5, d=2-5 = -3, n=20
Sn = n/2 [2a + (n-1)d] =
20/2 [2 × 5 + (20-1)(-3)] = -470
Solution:
The nos. are 24, 30,36,…………………..96
Here, a = 24, d = 6 & tn
= 96
Then n= ?
As tn = a + (n-1)d = 96
⟹ 24 + (n-1) × 6 = 96
⟹ (n-1) × 6 = 72
⟹ n = 13 (Ans.)
Solution:
Here common difference = d = 9 , so
the series is in AP.
a = 6 , tn =
last term = 105
so, n = ?
tn = a +
(n-1)d = 105
⟹ 6 + (n-1) × 9 = 105
⟹ (n-1) × 9 = 99
⟹ n = 12
Sum = n/2 [a + tn] = 12/2
[6 + 105] = 666 (Ans.)
A GP is a sequence in which the terms
increase or decrease by a constant ratio, called Common Ratio.
Let a, ar, ar², ar³ …………… are said to be in G.P, in which
1st term = a, Common Ratio = r & n= no. of terms
1. nth term or last term = tn = arⁿ⁻¹
2.
Sum of ‘n’ terms = Sn is given by
Sn =
a (1-rⁿ)/(1-r) , where r < 1
Sn =
a (rⁿ -1)/(r-1) , where r > 1
Examples
1. 1. How many
terms are there in G.P 3,6,12,24,………..,384
Solution:
Here a= 3, r=6/3 = 2, n= ?
last term = tn
= arⁿ⁻¹ = 3 × 2ⁿ⁻¹ = 384
⟹ 2ⁿ⁻¹ = 128 = 27
⟹ n – 1 =
7
⟹ n = 8 (Ans.)
Solution:
Here r = 2 , a = 2 , n =9
Then, Sn = a (rⁿ -1)/(r-1)
= 2 (2⁹ - 1)/ (2-1) = 1022 (Ans.)
Harmonic Progression (H.P)
A sequence
is said to be in H.P, if the reciprocal of the terms are in A.P.
If
‘a’ & ‘b’ are said to be in H.P,
when 1/a and 1/b are in A.P.
Arithmetic Mean and Geometric Mean
Arithmetic Mean (AM) |
Geometric Mean (GM) |
If a, b, c are in AP, then b = (a + c)/2 where b is called the AM of series a, b, c. Similarly, for n terms series, AM = (a₁ + a₂ + a₃ +…………+ aₙ) / n |
If a, b, c are in GP, then b =√(ac) where b is called the GM of series a, b, c. Similarly, for n terms series, GM = (a₁ × a₂ × a₃ ×…………× aₙ)¹/ⁿ |
Do it yourself
- If the first term of a G.P. is 20 and the common ratio is 4. Find the 5th term. (Ans.5120)
- The sum of the first three terms of a G.P. is 21/2 and their product is 27. Find the common ratio. (Ans. 2 &1/2)
- If the nth term of a GP is 128 and both the first term a and the common ratio r are 2. Find the number of terms in the GP. (Ans. n=7)
- What is the sum of the following series? -64, -66, -68, ..... , -100.
- Find the first term of the AP series in which 10th term is 6 and 18th term is 70. (Ans. -66).
- Find the nth term of the series 3, 8, 13, 18,….. (Ans. 5n-2)
- Find the sum of the following infinite G. P. 1/3,1/9,1/27,1/81, ……. (Ans. 1/2)
- What is the sum of infinite geometric series with first term equal to 1 and common ratio is ½? (Ans.2)
- What is the sum of 6 + 7 + 8 + ........... + 16 ? (Ans.121)
- What is sum total of all the figures from 31 to 50? (Ans.810)
- What is the sum of the first 17 terms of an arithmetic progression if the first term is -20 and last term is 28 ? (Ans. 68)
- If A = 1 - 10 + 3 - 12 + 5 - 14 + 7 ....... upto 60 terms, then what is the value of A?
- How many terms are there in an AP whose first and fifth terms are -14 and 2 respectively and the sum of terms is 40 ? (Ans. 10)
Good questions as assignment
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